Question

(radical din 8 -radical din 2)la puterea 20
(9 -4 radical din 5 )la puterea 50 x (9 + 4 radical din 5 )la puterea 50
9radical din 3 -radical din 12)la puterea 16

dau 100 de puncte

Answer 1

$\boxed{\bold{1.}} \ (\sqrt8-\sqrt2)^{20}=(2\sqrt2-\sqrt2)^{20}=(1\sqrt2)^{20}=1^{20} \cdot 2^{\frac{20}{2}}= \\ =1^{20} \cdot 2^{10}=\boxed{\bold{1 \ 024}};\\ \boxed{\bold{3.}} \ (9\sqrt3-\sqrt{12})^{16}=(9\sqrt3-2\sqrt3)^{16}=(7\sqrt3)^{16}=\\=7^{16}\cdot 3^{\frac{16}{2}}=7^{16}\cdot 3^8=\boxed{\bold{7^{16}\cdot 6 \ 561}}$

Answer 2

(√8-√2)∧20=.⇒
√8=2√2=
(2√2-√2)∧20=⇒
√2∧20=2048
(9-4√5)∧50×(9+4√5)∧50=1∧50=1
(9√3-√12)∧16=
√12=2√3
(9√3-2√3)∧16=
(7√3)∧16
sucees