Question

Radical din 841
Radical din 500

Answer 1

$b) \sqrt{500} = \sqrt{2 \times 2 \times 5 \times 5 \times 5} = \sqrt{(2 \times 2) \times (5 \times 5) \times 5} = \sqrt{ {2}^{2} \times {5}^{2} \times 5 } = (2 \times 5) \sqrt{5} = 10 \sqrt{5}$