Question

radical din x-1 + radical din x+3=2 
eucuatii iratinale 
Va rg ajutati.ma !!1

Answer 1

√(x+1)+√(x+3)=2
(√x+1)²+(√x+3)²=2²
x+1+x+3=4
2x=4-4
x=0

Answer 2

√(x-1)+√(x+3)=2 se ridica la patrat egalitatea
x-1+2√(x-1)√(x+3)+x+3=4
2x+2+2√(x²-x+3x-3)=4
2√(x²+2x-3)=2-2x    simplificam cu 2
√(x²+2x-3)=1-x ridicam din nou la patrat
x²+2x-3=1-2x+x²
4x=4
x=1

Answer 3

√(x-1)+√(x+3)=2 se ridica la patrat egalitatea
x-1+2√(x-1)√(x+3)+x+3=4
2x+2+2√(x²-x+3x-3)=4
2√(x²+2x-3)=2-2x    simplificam cu 2
√(x²+2x-3)=1-x ridicam din nou la patrat
x²+2x-3=1-2x+x²
4x=4
x=1