Question

Radical din x la a doua -4 + radical x-2=0

Answer 1

$\sqrt{x {}^{2} - 4} + \sqrt{x - 2} = 0 \\ = \sqrt{x {}^{2} - 4 } = - \sqrt{x - 2} \\ = x {}^{2} - 4 = x - 2 \\ (x - 2) \times (x + 2) = x - 2 \\ (x - 2) \times (x + 2) - (x - 2) = 0 \\ (x - 2) \times (x + 2 - 1) = 0 \\ (x - 1 - 2) \times (x + 1) = 0 \\ x - 2 = 0 \\ x - 1 = 0 \\ x = 2 \\ x = - 1 \\ \sqrt{2 {}^{2} - 4 } + \sqrt{2 - 2} = 0 \\ \sqrt{( - 1) {}^{2} - 4} + \sqrt{ - 1 - 2} = 0 \\ 0 = 0 \\ 2 \sqrt{ - 3} = 0 \\ x = 2 \\ x \: diferit \: - 1 \\ x = 2$