Question

(Radical din3-1)(radical din 6+2)

Answer 1

Răspuns:

$( \sqrt{3} - 1)( \sqrt{6} + 2) = \sqrt{18} + 2 \sqrt{3} - \sqrt{6} - 2$

$= 3 \sqrt{2} + 2 \sqrt{3} - \sqrt{6} - 2$

Answer 2

Salut!

(√3-1)(√6+2)=

=√18+2√3-√6-2

=3√2+2√3-√6-2

Succes!