Question

radical din45+radical125+radical din20

Answer 1

$\sqrt{45}+ \sqrt{125}+ \sqrt{20}= \\ \\ = \sqrt{9 \cdot5}+ \sqrt{25 \cdot 5}+ \sqrt{4 \cdot 5} = \\ \\ =3 \sqrt{5}+5 \sqrt{5}+ 2\sqrt{5} = \\ \\ =10 \sqrt{5}.$

Answer 2

$\sqrt{45} + \sqrt{125} + \sqrt{20} =$
$= \sqrt{9*5} + \sqrt{25*5} + \sqrt{4*5} =$
$=3 \sqrt{5} +5 \sqrt{5} +2 \sqrt{5}=$
$=10 \sqrt{5}$