Question

Radical mare din 1 supra 4 + radical mare din 1 supra 9 + radical mare din 49 supra 36 ? 

Answer 1

$\sqrt{ \frac{1}{4} } + \sqrt{ \frac{1}{9} } + \sqrt{ \frac{49}{36} } = \frac{ \sqrt{1} }{ \sqrt{4} } + \frac{ \sqrt{1} }{ \sqrt{9} } + \frac{ \sqrt{49} }{ \sqrt{36} } = \frac{1}{2} + \frac{1}{3} + \frac{7}{6} = \frac{3}{6}+ \frac{2}{6} + \frac{7}{6} =$$\frac{3+2+7}{6} = \frac{12}{6} =2$