Question

radical notez cu x pentru ca nul pot face .trebuie sa duc la forma cea mai simpla expresiile
a)2-2x2+x3-x5-x6+x6pe 2+x3-x5
b)(x2+x3)(2-x6+x7)-x21pe x7-1
va rog mult  \
ma poate ajuta cineva?//???????????

Answer 1

a) 2-2√2+√3-√5-√6+√6=2-2√2+√3-√5/2+√3-√5=2+√3-√5-2√2/2+√3-√5=1-2√2/2+√3-√5
b)(√2+√3)(2-√6+√7)-√21/√7-1, rationalizez inm cu √7+1 , iar la numitor obtin 7-1=6

numarat devine (√2+√3)(2-√6+√7)(√7+1)-√21(√7+1)= (    ) (  )(  )-√7×√3(√7+1)= .........-.7√3+√7√3= (√2√7+√3√7+√2+√3)(2-√2√3+√7)-7√3+√7√3=2√2√7+2√3√7+2√2+2√3-2√3√7-3√2√7-2√3-3√2+7√2+7√3+√2√7+√3√7-7√3+√7√3=2√2-2√3-3√2+7√2+7√3-7√3=6√2-2√3