Question

radical tine pana la egal x ^3+x^2-x-6=x

Answer 1

$\sqrt{x^3+ x^{2} -x-6}=x;x \geq 0 \\ x^3+ x^{2} -x-6= x^{2} \\ x^3-x-6=0 \\ x^3-8-x +2=0 \\ (x^3-2^3)-(x-2)=0 \\ (x-2)( x^{2} +2x+4)-(x-2)=0 \\ (x-2)[ x^{2} +2x+4-1]=0 \\ x-2=0 sau x^{2} +2x+3=0 \\ x=2$