Question

Radical x patrat - 8x +16 ( asta cuprinde tot radicalul ) =3

Answer 1

$\sqrt{x^2-8x+16} = \sqrt{(x-4)^2} = |x-4|$

Si:

$|x-4| = 3 \Rightarrow x-4= \pm 3\\\Rightarrow x=3+4 = 7\\sau\\x=-3+4=1$