Question

(|radical3-1supra 2|+ |rad3-2supra6|+|2rad3-4supra4|):5rad3supra rad300
| |e modoul

Answer 1

[tex](|\frac{\sqrt3-1}{2}|+|\frac{\sqrt3-2}{6}|+|\frac{2\sqrt3-4}{4}|):\frac{5\sqrt3}{\sqrt{300}}=\\ (\frac{\sqrt3-1}{2}+\frac{2-\sqrt3}{6}+\frac{4-2\sqrt3}{4}):\frac{5\sqrt3}{10\sqrt3}=\\ (\frac{\sqrt3-1}{2}+\frac{2-\sqrt3}{6}+\frac{2-\sqrt3}{2})\cdot 2=\\ (\frac{1}{2}+\frac{2-\sqrt3}{6})\cdot 2=\\ \frac{5-\sqrt3}{6}\cdot 2=\frac{5-\sqrt3}{3}[/tex]