Question

Radical32-radical50+radical8-radical242
Rezolvare clasa 7 va rog eu mult

Answer 1

√32-√50+√8-√242=4√2-5√2+2√2-11√2=-10√2

Answer 2

$\sqrt{32} - \sqrt{50} + \sqrt{8} - \sqrt{242} =4 \sqrt{2} -5 \sqrt{2} +2 \sqrt{2} -11 \sqrt{2} = \\ =- \sqrt{2} +2 \sqrt{2} -11 \sqrt{2} = \sqrt{2} -11 \sqrt{2} =-10 \sqrt{2}$