Question

(Radical8-radical2)(radical32+radical18)
Repede ca rog

Answer 1

$( \sqrt{8} - \sqrt{2} )( \sqrt{32} + \sqrt{18} )$

$= (2 \sqrt{2} - \sqrt{2} )(4 \sqrt{2} + 3 \sqrt{2} )$

$= \sqrt{2} \times 7 \sqrt{2}$

$= 7 \sqrt{4}$

$= 7 \times 2$

$= 14$

Answer 2

√8=2√2     √32=4√2      √18=3√2

(2√2 - √2)(4√2 + 3√2)=

√2 × 7√2=

7 (√2×√2)= 7 × 2=14

Sper că te-am ajutat!