Question

(radicaldin72+radical din 8)/radical din 2-(0,75+0,5din patrat)din patrat=

Answer 1

[tex] \frac{ \sqrt{72}+ \sqrt{8} }{ \sqrt{2} }-(0,75- 0,5^{2})^{2}= \\ \frac{ 6\sqrt{2}+2 \sqrt{2} }{ \sqrt{2} }-(0,75-0,25)^{2}= \\ \frac{8 \sqrt{2} }{ \sqrt{2} } -0,5^{2}= \\ 8-0,25=7,75 [/tex]