Question

rapid pls ................​

Answer 1

Răspuns:

Sper că te-am ajutat! Succes!

Answer 2

Explicație pas cu pas:

a)

$\frac{3}{x + 2} \in \mathbb{Z} \implies (x + 2) \in \mathcal{D}_{3} \\ \implies (x + 2) \in \Big\{- 3; - 1; 1; 3\Big\}\Big|( - 2) \\ \implies x \in \Big\{- 5; - 3; - 1; 1\Big\}$

x ∈ N => A = {1}

b)

$\frac{3}{x + 2} \in \mathbb{N} \implies (x + 2) \in \mathcal{D}_{3} \\ \implies (x + 2) \in \Big\{1; 3\Big\}\Big|( - 2) \\ \implies x \in \Big\{- 1; 1\Big\}$

x ∈ Z => A = {-1; 1}

c)

$\frac{3}{x + 2} \in \mathbb{Z} \implies (x + 2) \in \mathcal{D}_{3} \\ \implies (x + 2) \in \Big\{- 3; - 1; 1; 3\Big\}\Big|( - 2) \\ \implies x \in \Big\{- 5; - 3; - 1; 1\Big\}$

x ∈ Z => A = {- 5; - 3; - 1; 1}