Question

rapid va rog dau puncte​

Answer 1

a)∠AOB si ∠BOC sunt adiacente suplementare deci ∠AOB+∠BOC=180°

∠AOB=x°-11

∠BOC=2x°+11

x°-11°+2x°+11°=180° (-11°+11°=0 deci ei dispar)

3x=180°  l  : 3

x=60°

∠AOB=49°

∠BOC=131°

b) poza

c) poza

d)∠AOM;∠MOB;∠BON;∠NOC adiacente

e)OM=bisectoare ∠AOB=> ∠AOM = ∠MOB = 45°:2 = 22°30'

  ON=bisectpare ∠BOC=> ∠BON = ∠NOC = 131°:2 = 65°30'

   m(∠MON)=m(∠MOB)+m(∠BON)=22°30' + 65°30' =  88°