Question

Raport atomic si masa moleculara
sulfat de cupru

azotat de argint

sulfura de magneziu

hidroxid de sodiu

monoxid de carbon

acid fosforic

acid azotos

acid clorhidric
dau corona help me

Answer 1

Răspuns:

Explicație:

CuSO4

r.a.=1 : 1 :4

M=64 + 32 +4.16= 160--------> 160g/moli

AgNO3

r.a.= 1 : 1 :3

M= 108 + 14 + 3.16=170-------> 170g/moli

MgS

r.a.= 1 : 1

M=24 +32= 56-------> 56g/moli

NaOH

r.a.= 1: 1: 1

M = 23 + 16 +1=40------->40g/moli

CO

r.a.= 1: 1

M=12 + 16=18-------> 28g/moli

H3PO4

r.a.= 3 : 1 : 4

M= 3 + 31 + 4.16= 98-----------> 98g/moli

HNO2

r.a.= 1 : 1 : 2

M= 1 +14 + 2.16  =47--------> 47g/moli

HCl

r.a.=1 : 1

M= 1 + 35,5=36,5-------> 36,5g/moli