Question

Raportul atomic,raportul mesei si compozitia proncentuala a urmatoarelor elemente H2O , Na2O si AlCl3.Cum se afla?.Multumesc

Answer 1

              raport nr. atomi       raport de masa          compozitia procent.
H2O       H:O = 2:1           mH/mO=2/16=1/8  %H=2/18·100=11,11    %O = 16/18 ×100 = 88,88

Na2O      Na:O =2:1  mNa:mO=2·23:16=23:8   %Na=46/62·100=74,19 %  %O=16/62 =25,81

AlCl3      Al:Cl=1:3     mAl:mCl =27:(3·35,5)=27:106,5   %Al=27/133,5 ·100 = 20,22   %Cl =106.5/133,5 ·100 = 79,78