Question

Raportul masurilor a 2 unghiuri suplementare este 100 supra 50 . Aflati unghiurile.

Answer 1

Fie A,B doua unghiuri
∡A+∡B=180°
$\frac{A}{B}$=$\frac{100}{50}$
50A=100B
=>A=$\frac{100B}{50}$
$\frac{100B}{50}$+B=180°
100B+50B=9000
150B=9000
=>B=60°
A=180°-60°
A=120°

Answer 2

$\frac{m(\angle A)}{m(\angle B)} = \frac{100}{50} = 2\implies m(\angle A)=2m(\angle B)$
$m(\angle A)+m(\angle B) = 180^o$
$2m(\angle B)+m(\angle B)=180^o\implies m(\angle B) = 180^o:3 = 60^o$
$m(\angle A) = 180^o-m(\angle B) = 180^o-60^o=120^o$