Question

rationalizati numitorii​

Answer 1

Salut!

Exercitiul 4:

$\frac{11}{2\sqrt{6}-\sqrt{2}}$ = $\frac{11(2\sqrt{6}-\sqrt{2})}{22} = \frac{2\sqrt{6}-\sqrt{2}}{2} = \sqrt{6} - \sqrt{2}$

$\frac{-2}{\sqrt{9}-\sqrt{5} } = \frac{-2(\sqrt{9}+\sqrt{5})}{4} = \frac{\sqrt{9}+\sqrt{5}}{-2} = \frac{3-\sqrt{5} }{-2}$

Asta e cum am rezolvat eu....