Question

Rationalizați numitorii următoarelor rapoarte:

va rog macar o parte din ele​

Answer 1

Raspuns !!!!!!!!!!!!

Answer 2

Răspuns:

a)

$\frac{1}{2 - \sqrt{3} } = \frac{2 + \sqrt{3} }{4 - 3} = 2 + \sqrt{3}$

b)

$\frac{3}{ \sqrt{5} - \sqrt{2} } = \frac{3( \sqrt{5} + \sqrt{2} ) }{5 - 2} = \sqrt{5} + \sqrt{2}$

c)

$\frac{ - 2}{ \sqrt{7} + \sqrt{3} } = \frac{ - 2( \sqrt{7} - \sqrt{3} )}{7 - 3} = \frac{ - ( \sqrt{7} - \sqrt{3} ) }{2}$

d)

$\frac{11}{2 \ + \sqrt{5} } = \frac{11(2 - \sqrt{5}) }{ - 1} = - 11(2 - \sqrt{5} )$

e)

$\frac{ - 5}{4 + \sqrt{11} } = \frac{ - 5(4 - \sqrt{11} )}{16 - 11} = \sqrt{11} - 4$

f)

$\frac{18}{5 - \sqrt{13} } = \frac{18(5 + \sqrt{13}) }{25 - 13} = \frac{9(5 + \sqrt{13}) }{4}$

g)

$\frac{9}{ \sqrt{21} - \sqrt{18} } = \frac{9( \sqrt{21} + \sqrt{18} )}{21 - 18} = 3( \sqrt{21} - 3 \sqrt{2} )$

h)

$\frac{14}{ \sqrt{24} + \sqrt{17} } = \frac{14( \sqrt{24} - \sqrt{17}) }{24 - 17} = 2(2 \sqrt{6} - \sqrt{17} )$

i)

$\frac{ - 33}{8 - \sqrt{20} } = \frac{ - 33(8 + \sqrt{20} )}{64 - 20} = \frac{ - 3(8 + 2 \sqrt{5} )}{4}$

j)

$\frac{4}{5 + \sqrt{11} } = \frac{4(5 - \sqrt{11} )}{25 - 11} = \frac{2(5 - \sqrt{11}) }{7}$

k)

$\frac{3}{6 + \sqrt{33} } = \frac{3(6 - \sqrt{33} )}{36 - 33} = 6 - \sqrt{33}$

l)

$\frac{8}{7 - \sqrt{41} } = \frac{8(7 + \sqrt{41}) }{49 - 41} = 7 + \sqrt{41}$