Question

Rationalizati numitorul:
4\√12

calculati:
(4√3-3)(4√3+3)
(4√18+3√8)*(4√18-3√8)

Ajuati-ma urgent.

Dau coroana

Answer 1

4/rad 12 simplifici prin radical din 12 si obtii: 4*2 rad din 3 /12 simplifici prin 6 si obtii radical din 3 /2
1).....=(4 rad3)^2-3^2=48-9=39
2)...(4rad18 )^2-(3 rad8)^2=288-72=216

Answer 2

$\displaystyle \frac{4}{ \sqrt{12} } = \frac{4}{2 \sqrt{3} } = \frac{4 \sqrt{3} }{6} = \frac{2 \sqrt{3} }{3} \\ \\ (4 \sqrt{3} -3)(4 \sqrt{3} +3)=48-9=39 \\ \\ (4 \sqrt{18} +3 \sqrt{8} )(4 \sqrt{18} -3 \sqrt{8} )=288-72=216$