Question

Rationalizati numitorul
a)4/3rad3
b)12/5-rad7

Answer 1

$a) \frac{4}{3 \sqrt{3} } = \frac{4 \sqrt{3} }{3 \times 3} = \frac{4 \sqrt{3} }{9}$

$b) \frac{12}{5 - \sqrt{7} } = \frac{60 + 12 \sqrt{7} }{ {5}^{2} + { \sqrt{7} }^{2} } = \frac{12(5 + \sqrt{7}) }{25 - 7} = \frac{12(5 + \sqrt{7}) }{18} = \frac{2(5 + \sqrt{7}) }{3}$