Question

Rationalizati numitorul raportului:

√3 supra √3-√2

Answer 1

$\displaystyle \frac{ \sqrt{3} }{ \sqrt{3} - \sqrt{2} } = \frac{ \sqrt{3} ( \sqrt{3} + \sqrt{2} )}{3-2} = \frac{3+ \sqrt{6} }{ 1} =3+ \sqrt{6}$