Question

Rationalizati numitorul raportului:
√3 supra √3-√2.

Answer 1

Amplifici cu rad3+rad2, vei avea rad3(rad3+rad2) / 1, adica rad9+rad6=3+rad6

Answer 2

$\frac{\sqrt{3}}{ \sqrt{3}- \sqrt{2} }$

rationalizam prin $\sqrt{3} + \sqrt{2}$
si avem:

$\frac{ \sqrt{3}( \sqrt{3} - \sqrt{2})}{3-2} = \frac{3- \sqrt{6} }{1} = 3 - \sqrt{6}$