Question

Rationalizati numitorul raportului:
√3
supra
√3-√2

Answer 1

$\frac{\sqrt3}{\sqrt3-\sqrt2}=\frac{\sqrt3(\sqrt3+\sqrt2)}{(\sqrt3-\sqrt2)(\sqrt3+\sqrt2)}=\frac{\sqrt3(\sqrt3+\sqrt2)}{3-2}=\sqrt3(\sqrt3+\sqrt2)$

Answer 2

√3/(√3-√2)  = (√3(√3+√2))/(√3-√2)(√3+√2)= (3+√6)/(3-2) = 3+√6

sper sa intelegi