Question

rationalizeaza fractia 2 supra radical din 2 minus radical din 3 minus 1

Answer 1

2/(√2-√3-1)=
=2(√2-√3+1)/(√2-√3-1)(√2-√3+1)=
=2(√2-√3+1)/[(√2-√3)²-1)=
=2(√2-√3+1)/(2-2√6+3-1)=
=2(√2-√3+1)/(4-2√6)=
=(√2-√3+1)/(2-√6)=
=(√2-√3+1)(2+√6)/(2-√6)(2+√6)=
=(2√2-2√3+2+√12-√18+√6)/(-2)=
=(2√2-2√3+2+2√3-3√2+√6)/(-2)=
=(2-√2+√6)/(-2)=
=(√2-2-√6)/2