Question

Reactioneaza 400g solutie HCl de concentratie 36,5 la suta cu zincul.Ce masa de clorura de zinc se obtine?Cat zinc se consuma in reactie?

Answer 1

Zn + 2 HCl => ZnCl2 + H2
c = md/ms * 100
md = ms*c/100 = 400*36,5/100 = 146 g HCl
2*36,5 g HCl..............136 g ZnCl2
146 g HCl...................x g ZnCl2 
x = 272 g ZnCl2
2*36,5 g HCl..............65 g Zn
146 g HCl...................x g Zn 
x = 130 g Zn