Question

reactioneaza 560 g de fier 10% impuritati cu HCl 20%. Se cere: ecuatia chimica, masa de fier pur, masa de solutie HCl consumata

Answer 1

56g....73g
Fe + 2HCl --> FeCl2 + H2
504g...x=657g Avem 10% impur si 90% pur..90/100*560=504g Fe pur
Cp=md/ms*100==>ms=md*100/Cp=657*100/20=3285g HCl
MFe=56g/mol
MHCl=36.5g/mol