Question

reconstituit adunarea abc+bc+c=1081



metoda mai simpla va rog​

Answer 1

a̅b̅c̅ + b̅c̅ + c̅ = 1081

100a+10b+c+10b+c+c = 1081

100a+20b+3c = 1081

3c-1 = 1080-100a-20b

3c-1 = 20(54-5a-b)

3c-1 e divizibil cu 20 ⇒ c = 7 (singura posibilitate.)

20 = 20(54-5a-b)

54-5a-b = 1

5a+b = 53

⇒ a = 9, b = 8 (singura posibilitate.)

987 + 87 + 7 = 1081