Question

Repede!
1. (5+10+15+...+55):(1+2+3+...+11)
(12²-5²) la puterea 73 : 119 la puterea 73
2. 1*2*3*4*....*99+3)
2 la puterea 78-2 la puterea 77-2 la puterea 76- 2 la puterea 75-2 la puterea 74-2 la puterea 73

Answer 1

1. (5+10+15+...+55):(1+2+3+...+11)=

=5(1+2+3+...+11):(1+2+3+...+11)=5

(12²-5²)⁷³ : 119⁷³ =(144-25) ⁷³ : 119⁷³ = 119⁷³:119⁷³ =1

2. 1*2*3*4*....*99+3

cu semnul *  este un numar foarte mare pentru a fi calculat 

 daca in loc de * era +

1+2+3+....99+3=99(99+1)/2+3=99*50+3=4950+3=4953

 

2⁷⁸-2⁷⁷-2⁷⁶- 2⁷⁵-2⁷⁴-2⁷³= 2⁷³(2⁵-2⁴-2³-2²-2¹-2⁰)=2⁷³ (32-16-8-4-2-1)=2⁷³* 1=2⁷³