Question

Repede am teză acum. ​Pls

Answer 1

1.

A intersectat cu B = (2003; 2014]

2.

$| - 3| + | - 5| \times 2$

3+5×2= 3+10= 13

3.

NU INTELEG CERINTA

4.

a= 2-4

a= -2

b= 3-9

b= -6

c= 4-16

c= -12

c<b<a

-12; -6; -2

5.

$a = (3 + \sqrt{6} ) {}^{2} + (3 - \sqrt{6} ) {}^{2}$

$a = \sqrt{(3 + \sqrt{6} ) {}^{2} } + \sqrt{(3 - \sqrt{6} ){}^{2} }$

$a = |3 + \sqrt{6} | + |3 - \sqrt{6} |$

a=0

0 =N => a apartine lui N

LA 3 NU INTELEG CERINTA!

MULT SUCCES LA TEZA :))