Question

Repede!! Dau coroana

3^12:3^10+(3x5)^10:(3+5)^10:15^9-2011^0x1^2011

Answer 1

Răspuns:

cred ca ai undeva o greseala in enunt, asa cum e scris ajungi la urmatorul rezultat

Explicație pas cu pas:

$3^{12}:3^{10} + (3\cdot5)^{10}:(3+5)^{10}:15^9 - 2011^0\cdot1^{2011} =$

$=3^{12-10} + (15)^{10}:(8)^{10}:15^9 - 1\cdot1 =$

$=3^{2} + (15)^{10-9}:(2^3)^{10} - 1 =$

$=3^{2} + 15:(2)^{30} - 1$

Answer 2

Răspuns:

3¹²÷3¹⁰+(3•5)¹⁰÷15⁹-2011⁰•1²⁰¹¹=

3¹²⁻¹⁰+15¹⁰⁻⁹-1·1=

3²+15¹-1=

9+15-1=

23

am analizat ex si am constatat ca ai scris de 2 ori o paranteza