Question

repede va rog (100 pct)​

Answer 1

Răspuns:

a) P(ABCD) = 4AB = 4×10m = 40 m

b) A(ABCD) = AB² = (10m)² = 100 m²

A(O ; Q) = 2×π×NO² = 2×4×π = 8π m²

A(ABCD) - A(O ; Q) = 100m² - 8πm² = 4(25 - 2π) m²

c) AM = AB/2 = 10m/2 = 5 m

2MN = 10m - (NS+SP) = 10m - 8m = 2m

MN = 2m/2 = 1m

(NS) = 2π×NS/2 = NS×π = 2π m

(SP) = (NS) => (SP) = 2π m

PR = MN => PR = 1 m

RC = CD/2 = 10m/2 = 5 m

D = AM+MN+(NS)+(SP)+PR+RC

= 5m + 1m + 4π m + 1m + 5m

= 12 m + 4×3,14 m

= 12 m + 12,56 m

= 24, 56 m < 25 m