Question

REPEDE, VĂ ROG. DAU CORONA?
$4 \sqrt{6 } + 2 \sqrt{2} \times (6 \sqrt{2} - 2 \sqrt{3))}$
va rog​

Answer 1

c

$3 \sqrt{5} - 7( \sqrt{2} + (15 \sqrt{5} - 3 \sqrt{5} + 12 \sqrt{2} ) \div 12) = 3 \sqrt{5} - 7( \sqrt{2} + (12 \sqrt{5} + 12 \sqrt{2} ) \div 12) = 3 \sqrt{5} - 7( \sqrt{2} + \sqrt{5} + \sqrt{2} ) = 3 \sqrt{5} - 14 \sqrt{2} - 7 \sqrt{5} = - 14\sqrt{2} - 4 \sqrt{5}$

d

$4 \sqrt{6} + 2 \sqrt{2} (6 \sqrt{2} - 2(3 \sqrt{2} - 2 \sqrt{3} )) = 4 \sqrt{6} +2 \sqrt{2} (6 \sqrt{2} - 6 \sqrt{2} + 4 \sqrt{3} ) = 4 \sqrt{6} + 8 \sqrt{6} = 12 \sqrt{6}$

e

$16 + 3 \sqrt{7} (21 \sqrt{3} - 3(7 \sqrt{3} + 2 \sqrt{7} )) = 16 + 3 \sqrt{7} (21 \sqrt{3} - 21 \sqrt{3} - 6 \sqrt{7} ) = 16 - 126= - 110$

f

$13 \sqrt{2} + 2 (15 \sqrt{3} - 3(12 \sqrt{2} - 5 \sqrt{2} + 5 \sqrt{3} )) = 13 \sqrt{2} + 2(15 \sqrt{3} - 24 \sqrt{2} - 15 \sqrt{3} ) = 13 \sqrt{2} - 48 \sqrt{2} = - 35 \sqrt{2}$

g

$180 \sqrt{5} + 4 \sqrt{5} (18 \sqrt{2} - 3 \sqrt{5} (8 \sqrt{10} - 6 \sqrt{10} + 3 \sqrt{5} )) = 180 \sqrt{5} + 4 \sqrt{5} (18 \sqrt{2} - 30 \sqrt{2} - 45) = 180 \sqrt{5} + 4 \sqrt{5}( - 12 \sqrt{2} - 45) = 180 \sqrt{5} - 48 \sqrt{10} - 180$