Question

repede va rog repede ,dau coroana ,repede
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Answer 1

$\bf 1.\\ \\ \it a)\ \dfrac{11}{4}-x=\dfrac{3}{2} \Rightarrow\dfrac{11}{4}-\dfrac{^{2)}3}{\ 2}=x \Rightarrow x=\dfrac{5}{4}\\ \\ \\ b)\ 2\dfrac{1}{3}+x=3\dfrac{1}{9} \Rightarrow x=\dfrac{28}{9}-\dfrac{^{3)}7}{\ 3} \Rightarrow x=\dfrac{7}{9}\\ \\ \\ d)\ x\cdot\dfrac{2}{3}=7 \Rightarrow x=7:\dfrac{2}{3}\Rightarrow x=7\cdot\dfrac{3}{2}\Rightarrowx=\dfrac{21}{2}\\ \\ \\ f)\ x:\dfrac{5}{9}=\dfrac{1}{2} \Rightarrow x=\dfrac{1}{2}\cdot\dfrac{5}{9} \Rightarrow x=\dfrac{5}{18}$

2.

$\it b)\ 9:\dfrac{1}{9}-80\dfrac{1}{9}=9\cdot\dfrac{9}{1}-80\dfrac{1}{9}=81-80\dfrac{1}{9}=\dfrac{8}{9}\\ \\ \\ h)\ \Big(2-\dfrac{1}{2}\Big)^2:\Big(\dfrac{3}{2}\Big)^2=\Big(\dfrac{3}{2}\Big)^2:\Big(\dfrac{3}{2}\Big)^2=1\\ \\ \\ j)\ \Big(3-\dfrac{1}{3}\Big)^2\cdot\Big(\dfrac{9}{8}\Big)^2=\Big(\dfrac{8}{3}\Big)^2:\Big(\dfrac{9}{8}\Big)^2=\Big(\dfrac{\not8}{\not3}\cdot\dfrac{\not9\ ^3}{\not8}\Big)^2=3^2=9$