Question

REPEDEEEEEEEEE. VA ROGGGGGGGGG

Answer 1

Răspuns:

Explicație pas cu pas:

$a) = \frac{2}{3} *\frac{16}{81} *\frac{64}{729} : \frac{1024}{59049} = \frac{32}{243} *\frac{64}{729} *\frac{59049}{1024} = \frac{32}{243}*\frac{81}{16} =\frac{2}{3}$

$b) = \frac{[(\frac{5}{6})^3]^9 }{(\frac{5}{6})^1^3 } = \frac{\frac{5^2^7}{6^2^7} }{\frac{5^1^3}{6^1^3} }= \frac{\frac{5^2^7}{5^1^3} }{\frac{6^2^7}{6^1^3} } = \frac{5^2^7^-^1^3}{6^2^7^-^1^3} =\frac{5^1^4}{6^1^4}$

$c) = \frac{[(\frac{7}{2})^1^0]^1^1 }{[(\frac{7}{2})^1^1]^1^0 } -1=\frac{\frac{7^1^1^0}{2^1^1^0} }{\frac{7^1^1^0}{2^1^1^0} } -1=\frac{7^1^1^0^-^1^1^0}{2^1^1^0^-^1^1^0} -1=\frac{7^0}{2^0}-1=\frac{1}{1} -1=1-1-=0$

$d) = \frac{1}{2}*\frac{1^9}{2^9}:(\frac{1^9^1}{2^9^1} )-(\frac{1^2}{2^2} ) = \frac{1}{2}*\frac{1}{512} :\frac{1^9^1}{2^9^1}-\frac{1}{4} =\frac{1}{1024}:\frac{1}{2^9^1} -\frac{1}{4} =\frac{1}{1024} *\frac{2^9^1}{1}-\frac{1}{4} =\frac{2^8^1}{1} -\frac{1}{4} =\frac{2^8^3}{4}-\frac{1}{4} =\frac{2^8^3-1}{4}$

Sper ca te-am ajutat! Bafta!