Question

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Answer 1

Răspuns: $\red{\LARGE\boxed{\bf 21,3}}$

Explicație pas cu pas:

$\large\bf 1,5\cdot\Bigg\{3+3,2\cdot\bigg[100\cdot 0,01 + \dfrac{5}{2} \cdot\bigg(14-\dfrac{6}{5}:0,1\bigg)\bigg]\Bigg\}-\dfrac{13-1}{9} : \dfrac{1}{9} =$

$\large\bf 1,5\cdot\Bigg\{3+3,2\cdot\bigg[1 + \dfrac{5}{2} \cdot\bigg(14-\dfrac{6}{5}:\dfrac{1}{10}\bigg)\bigg]\Bigg\}-\dfrac{12}{9} \cdot \dfrac{9}{1} =$

$\large\bf 1,5\cdot\Bigg\{3+3,2\cdot\bigg[1 + \dfrac{5}{2} \cdot\bigg(14-\dfrac{6}{\not5}\cdot\dfrac{\not10}{1}\bigg)\bigg]\Bigg\}-\dfrac{12}{\not9} \cdot \dfrac{\not9}{1} =$

$\large\bf 1,5\cdot\Bigg\{3+3,2\cdot\bigg[1 + \dfrac{5}{2} \cdot\bigg(14-6\cdot 2\bigg)\bigg]\Bigg\}-12 =$

$\large\bf 1,5\cdot\Bigg\{3+3,2\cdot\bigg[1 + \dfrac{5}{2} \cdot\bigg(14-12\bigg)\bigg]\Bigg\}-12 =$

$\large\bf 1,5\cdot\Bigg[3+3,2\cdot\bigg(1 + \dfrac{5}{\not2} \cdot \not2\bigg)\Bigg]-12 =$

$\large\bf 1,5\cdot\Bigg[3+3,2\cdot\bigg(1 + 5\bigg)\Bigg]-12 =$

$\large\bf 1,5\cdot\bigg(3+3,2\cdot 6\bigg)-12 =$

$\large\bf 1,5\cdot\bigg(3+19,2\bigg)-12 =$

$\large\bf 1,5\cdot 22,2 -12 =$

$\large\bf 33,3 -12 =$

$\red{\Large\boxed{\bf 21,3}}$

$\text{PS: Daca esti pe telefon gliseza spre stanga pentru a vedea rezolvarea}$

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