Question

repedeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Answer 1

Răspuns:

1.a); 2.c)

Explicație pas cu pas:

1.

$= -\bigg(\dfrac{^{6)} 13}{4} - \dfrac{^{3)}33}{8} + \dfrac{^{4)}13}{6}\bigg) + \bigg(\dfrac{4083-408}{900} - \dfrac{35}{6}\bigg) = -\bigg(\dfrac{78 - 99 + 52}{24}\bigg) + \bigg(\dfrac{3675^{(75} }{900} - \dfrac{35}{6}\bigg) = -\bigg(\dfrac{31}{24}\bigg) + \bigg(\dfrac{49}{12} - \dfrac{^{2)} 35}{6}\bigg) = -\dfrac{31}{24} + \bigg(\dfrac{49 - 70}{12}\bigg) = -\dfrac{31}{24} - \dfrac{^{2)} 21}{12} = -\dfrac{31 + 42}{24} = -\dfrac{73}{24} =\bf -3\dfrac{1}{24}$

2.

$4\sqrt{3} \cdot 16\sqrt{12} = 64\sqrt{3 \cdot 12} = 8^{2} \sqrt{36} = 8^{2} \sqrt{6^{2}} = 8^{2} \cdot 6}$

media geometrica:

$\sqrt{4\sqrt{3} \cdot 16\sqrt{12} } = \sqrt{8^{2} \cdot 6} =\bf 8\sqrt{6}$