Question

Respectand rolul parantezelor si ordinea efectuarii operatiilor , calculati :
a) √3a(a/√3-b√3)-√5b(-a/√5+√20b)=
b)√5a(2/√5)+√7a(8/√7+5√7a)-√2(x/√2-√50)=

Answer 1

a)√3a(a/√3-b√3)-√5b(-a/√5+√20b)=
     a²-3ab+ab-10b²=
     a²-2ab-10b²

b)√5a(2/√5)+√7a(8/√7+5√7a)-√2(x/√2-√50)=
    2a+8a+35a²-a+10=
    35a²+9a+10