Question

Restrângeti, după ce ați scos factorii de sub radicali:​

Answer 1

√32-√50+√8-√98+√242=4√2-5√2+2√2-7√2+11√2=5√2

-√162+√200-√72-√128+√18=-9√2+10√2-6√2-8√2+3√2=-10√2

√48-√75+√12+√243-√147=4√3-5√3+2√3+9√3-7√3=3√3

√300-√192-√108+√27-√432=10√3-8√3-6√3+3√3-12√3=-13√3

Answer 2

$a) \sqrt{32} - \sqrt{50} + \sqrt{8} - \sqrt{98} + \sqrt{242}$

$2{}^{2} \sqrt{2} - 5 \sqrt{2} + 2 \sqrt{2} - 7 \sqrt{2} + 11 \sqrt{2}$

$4 \sqrt{2} - 5 \sqrt{2} + 2 \sqrt{2} - 7 \sqrt{2} + 11 \sqrt{2}$

$5 \sqrt{2}$

$b) - \sqrt{162} + \sqrt{200} - \sqrt{72} - \sqrt{128} + \sqrt{18}$

$- 9 \sqrt{2} + 10 \sqrt{2} - 6 \sqrt{2} - 2 {}^{3} \sqrt{2} + 3 \sqrt{2}$

$- 9 \sqrt{2 } + 10 \sqrt{2} - 6 \sqrt{2} - 8 \sqrt{2} + 3 \sqrt{2}$

$- 10 \sqrt{2}$

$c) \sqrt{48} - \sqrt{75} + \sqrt{12} + \sqrt{243} - \sqrt{147}$

$4 \sqrt{3} - 5 \sqrt{3} + 2 \sqrt{3} + 3 {}^{2} \sqrt{3} - 7 \sqrt{3}$

$4 \sqrt{3} - 5 \sqrt{3} + 2 \sqrt{3} + 9 \sqrt{3} - 7 \sqrt{3}$

$3 \sqrt{3}$

$d) \sqrt{300} - \sqrt{192} - \sqrt{108} + \sqrt{27} - \sqrt{432}$

$10 \sqrt{3} - 8 \sqrt{3} - 6 \sqrt{3} + 3 \sqrt{3} - 12 \sqrt{3}$

$- 13 \sqrt{3}$