Question

Restrangeti,dupa ce ati scos factorii de sub radicali:
a)5√6+4√24+6√54-2√150
b)√27+√243+√75-√108
c)5√162+10√12-6√75-3√50
d)√72-√98+√128
e)-3√98+2√162+5√147-√432
f)0,2√75-$\frac{5}{4}$√48+2,(6)×√27
l)$\frac{1}{3}$√18+$\frac{2}{5}$√50-$\frac{3}{4}$√32+√320
Imi aratati si rezolvareaa va rog !!!

Answer 1

a)5√6+4√24+6√54-2√150=
=5√6+8√6+18√6-10√6=21√6

b)√27+√243+√75-√108=
=3√3+9√3+5√3-6√3=11√3

c)5√162+10√12-6√75-3√50=
=45√2+20√3-30√3-15√2=30√2-10√3


d)√72-√98+√128=
=6√2-7√2+8√2=7√2

e)-3√98+2√162+5√147-√432=
=-21√2+18√2+35√3-12√3=-3√2+23√3


f)0,2√75-5/4√48+2,(6)×√27=
=√3-5√3+24/9×3√3=
=√3-5√3+8/3×3√3=
=√3-5√3+8√3=4√3


l)1/3√18+2/5√50-3/4√32+√320=
=√2+2√2-3√2+8√5=8√5