Question

restrangeti patratul unei sume sau diferente(formula(a+b)² / (a-b)²):
x²-2x+1=?
9x²-24x+16=?
3x²-2√6x+2=?
descompuneti folosind formula diferentei/sumei:
x²-16x=?
25x²-36=?
scoateti factorul comun:
2x-4y+10z+12t=?
5(2x-3)-x(2x-3)=?
√150xla puterea a4ay²-√24x²yla puterea a4a+√96x³y³=?
4√7x²(x+1)+8√7(x+1)+18√3(x+1)=?

Answer 1

a) x²-2x+1 = (x-1)²
b) 9x²-24x+16 = (3x-4)²
c) 3x²-2√6+2 = (x√3 - √2)²
x²-16 = (x-4)(x+4)
25x²-36 = (5x-6)(5x+6)
2x-4y+10z+12t= 2(x-2y+5z+6t)
5(2x-3)-x(2x-3)= (2x-3)(5-x)
=√150$x^{4}$y²-√24x²$y^{4}$+√96x³y³=
=$x^{4}$y²5√6-x²$y^{4}$2√6+x³y³2√23=
=x²y²(x²5√6-y²2√6+xy2√25)

= 2(x+1)(2√7x²+4√7+9√3)