Question

Restrângeţi sumele: a 2√3+5√3-(7√3+2√3); da=12-√7; b=3√7+3; c= 2√7+ b 11√7+7√7-(3√7-5√7); c2√5-4√5+(2√5 +9√5-7√5): d√5+(-3√5 +6√5)-(-3√5-9√5); 2√6+3√3-(5√6-3√3)+(-3√6-9√3); +(-9√13+5√13)-(8√13-√13)+7√11: (3√2-2√3)+(-4√2-3√3)-(6√2-5√3).​

Answer 1

Salut!

a)$2\sqrt{3} +5\sqrt{3} -(7\sqrt{3} +2\sqrt{3} )=7\sqrt{3} -9\sqrt{3} =-2\sqrt{3}$

b)$11\sqrt{7} +7\sqrt{7} -(3\sqrt{7} -5\sqrt{7} )=18\sqrt{7} +2\sqrt{7} =20\sqrt{7}$

c)$2\sqrt{5} -4\sqrt{5} +(2\sqrt{5} +9\sqrt{5} -7\sqrt{5} )=-2\sqrt{5} +4\sqrt{5} =2\sqrt{5}$

d)$\sqrt{5} +(-3\sqrt{5} +6\sqrt{5} )-(-3\sqrt{5} -9\sqrt{5})=\sqrt{5} +3\sqrt{5} +12\sqrt{5} =16\sqrt{5}$

e)$2\sqrt{6} +3\sqrt{3} -(5\sqrt{6} -3\sqrt{3} )+(-3\sqrt{6} -9\sqrt{3} )=-3\sqrt{6} +6\sqrt{3}-3\sqrt{6} -9\sqrt{3} =-6\sqrt{6} -3\sqrt{3}$

f) $(-9\sqrt{13} +5\sqrt{13} )-(8\sqrt{13} -\sqrt{13} )+7\sqrt{11} =-4\sqrt{13} -7\sqrt{13} +7\sqrt{11} =-11\sqrt{13} +7\sqrt{11}$

g)$(3\sqrt{2} -2\sqrt{3} )+(-4\sqrt{2} -3\sqrt{3} )-(6\sqrt{2}-5\sqrt{3} )=-1\sqrt{2}-5\sqrt{3}-6\sqrt{2} +5\sqrt{3} =-7\sqrt{2} + 0=-7\sqrt{2}$

Sper ca te-am ajutat!

P.S:Coroana?