Question

Restringeti:

a) 25X²-10X+1
b)0,25X²+X+1
c)X³-6X²+12X-8
d)X³+3X²+3X+1

Answer 1

[tex](a+b)^{2}=a^2+2ab+b^2\\ a) 25 x^{2} -10x+1=(5x)^2-2*x*5*1+1^2=(5x-1)^2\\a=5; b=1\\ b) 0,25 x^{2} +x+1=(0,5x)^2+2*x*0,5*1+1^2=(0,5x+1)^2\\a=0,5; b=1\\[/tex]
[tex](a+b)^3=a^3+3a^2b+3ab^2+b^3\\(a-b)^3=a^3-3a^2b+3ab^2-b^3\\ c) x^{3}-6 x^{2} +12x-8=x^{3}-3* x^{2} *2+3*x*2^2-2^3=(x-2)^3\\ a=x; b=2\\ d) x^{3}+3 x^{2} +3x+1= x^{3}+3* x^{2} *1+3*x*1^2+1^3=(x+1)^3 \\a=x; b=1\\ [/tex]
Am folosit formulele de calcul prescurtat, care le-am scris mai sus!!!