Question

Resultatul calculului 2 radical din 2 minus 3 radical din 3 inchidem paranteza totul la 2 plus 2 deschidem paranteza radical din 3 plus 3 radical din 2 inchidem paranteza totul la 2 minus deschidem paranteza 5 radical din 2 minus 1 închidem paranteza pe langa 5 radical din 2 plus 1

Answer 1

Am anexat un raspuns ---

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Answer 2

$(2 \sqrt{2} - 3 \sqrt{3}) ^{2} + 2( \sqrt{3} + 3 \sqrt{2}) ^{2} - (5 \sqrt{2} - 1)(5 \sqrt{2} + 1) \\ \\ {(2 \sqrt{2}) }^{2} - 2 \times 2 \sqrt{2} \times 3 \sqrt{3} + (3 \sqrt{3}) ^{2} + 6 + 12 \sqrt{6} + 36 - {(5 \sqrt{2}) }^{2} + 1 \\ \\ {2}^{2} { \sqrt{2} }^{2} - 2 \times 2 \sqrt{2} \times 3 \sqrt{3} + (3 \sqrt{3}) ^{2} + 6 + 12 \sqrt{6} + 36 - {(5 \sqrt{2}) }^{2} + 1 \\ \\ 4 { \sqrt{2} }^{2} - 2 \times 2 \sqrt{2} \times 3 \sqrt{3} + {(3 \sqrt{3}) }^{2} + 6 + 12 \sqrt{6} + 36 - {(5 \sqrt{2}) }^{2} + 1 \\ \\ 4 \times 2 - 2 \times 2 \sqrt{2} \times 3 \sqrt{3} + (3 \sqrt{3}) ^{2} + 6 + 12 \sqrt{6} + 36 - {(5 \sqrt{2}) }^{2} + 1 \\ \\ 4 \times 2 - 2 \times 2 \sqrt{2} \times 3 \sqrt{3} + {3}^{2} { \sqrt{3} }^{2} + 6 + 12 \sqrt{6} + 36 - {(5 \sqrt{2}) }^{2} + 1 \\ \\ 4 \times 2 - 2 \times 2 \sqrt{2} \times 3 \sqrt{3} + 9 \times 3 + 6 + 12 \sqrt{6} + 36 - {(5 \sqrt{2}) }^{2} + 1 \\ \\ 4 \times 2 - 2 \times 2 \sqrt{2} \times 3 \sqrt{3} + 9 \times 3 + 6 + 12 \sqrt{6} + 36 - {5}^{2} { \sqrt{2} }^{2} + 1 \\ \\ 4 \times 2 - 2 \times 2 \sqrt{2} \times 3 \sqrt{3} + 9 \times 3 + 6 + 12 \sqrt{6} + 36 - 25 { \sqrt{2} }^{2} + 1 \\ \\ 4 \times 2 - 2 \times 2 \sqrt{2} \times 3 \sqrt{3} + 9 \times 3 + 6 + 12 \sqrt{6} + 36 - 25 \times 2 + 1 \\ \\ 8 - 2 \times 2 \sqrt{2} \times 3 \sqrt{3} + 9 \times 3 + 6 + 12 \sqrt{6} + 36 - 25 \times 2 + 1 \\ \\ 8 - 2 \times 2 \times 3 \sqrt{2 \times 3} + 9 \times 3 + 6 + 12 \sqrt{6} + 36 - 25 \times 2 + 1 \\ \\ 8 - 2 \times 6 \sqrt{6} + 9 \times 3 + 6 + 12 \sqrt{6} + 36 - 25 \times 2 + 1 \\ \\ 8 - 12 \sqrt{6} + 27 + 6 + 12 \sqrt{6} + 36 - 50 + 1 \\ \\ (8 + 27 + 6 + 36 - 50 + 1) + ( - 12 \sqrt{6} + 12 \sqrt{6}) = 28$