Question

rexolvati in r ecuatiile:x-1/5+x-2/3=2-x-2/15
5-x√5=3-x√3
(x-1)·√2=2x-1

Answer 1

x-1/5+x-2/3=2-x-2/15x+x+x=2-2/15+1/5+2/3
3x=(2·15-2+1·3+2·5)/15
3x=(30-2+3+10)/15
3x=41/15
3x·15=41
45x=41
x=41/45
x=0,9(1)

5-x√5=3-x√3
-x√5+x√3=3-5
x(√3-√5)=-2             
x=-2/(√3-√5)=-2(√3+√5)/(3-5)=-2(√3+√5)/-2
x=√3+√5

(x-1)·√2=2x-1
√2x-√2=2x-1
√2x-2x=√2-1
x(√2-2)=√2-1
x=(√2-1)/(√2-2)=(√2-1)(√2+2)/(2-4)=(2+2√2-√2-2)/-2=-√2/2
x=-√2/2