Question

rez in multimea nr reale: 2^(2x^2 -3-3) = 8

Answer 1

$2^{2x^2-3-3}=8$

$2^3=8=\textgreater 2x^2-3-3=3$

$2x^2=9$

$x^2=\frac{9}{2}$

$x=\sqrt{\frac{9}{2}}=\frac{\sqrt9}{\sqrt2}=\frac{3}{\sqrt2}=\frac{3\sqrt2}{2}$