Question

rezolva ecuația 2x^2-3x=0

Answer 1

$a=2 , b=-3 , c=0$
$2 x^{2} - 3x=0$ => Δ=$b^{2} -4ac = 9$
$x_{1,2} = \frac{-b+- \sqrt{delta} }{2a} = \frac{3+-3}{4} =\ \textgreater \ x_{1} = 0, x_{2} = \frac{3}{2}$