Question

Rezolvă ecuația (3-2i)z=5+i

Answer 1

Răspuns:

z=1+i

Explicație pas cu pas:

z=(5+i)/(3-2i)=(5+i)(3+2i)/(9+4)=(15-2+13i)/13=1+i

verificare

(3-2i) (1+i)=5+i

3+2+(3-2) i=1+i

1+i=1+i

adevarat , bine rezolvat

Answer 2

$(3-2i)z = 5+i\\\\ z = \dfrac{5+i}{3-2i} = \dfrac{(3+2i)(5+i)}{(3-2i)(3+2i)} = \dfrac{15+3i+10i-2}{9+4} = \dfrac{13+13i}{13} = \boxed{1+i}$